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The Ratio Of Voltage Sensitivity And Current Sensitivity Is
The Ratio Of Voltage Sensitivity And Current Sensitivity Is. A a) tends to decrease the output resistance b) tends to increase the output resistance7 c) does not. The sensitivity of a moving coil galvanometer is defined as the ratio of the change in deflection of the galvanometer to the change in current.
Current sensitivity can be increased by increasing the number of turns of the coil. Hence, there is no increase in voltage sensitivity. `v_(s_2) = (n_2b_2a_2)/(k_2r_2)` and, voltage sensitivity for m 1 is given as:
If A Galvanometer Gives A Bigger Deflection For A Little Current It Is Said To Be Sensitive.
Voltage sensitivity, v = ( n a b k) i r. Vs₂ = n₂b₂a₂/ k₂ r₂. Sensitivity is normally measured with a 1 watt power input or a 2.83 vrms voltage input.
Figure Of Merit Of A Galvanometer.
Voltage sensitivity = q v current sensitivity = q i also, potential difference, v = ig hence, v s i s = q / v q / i = i v = i ig ∴ v s i s = 1 g Similarly voltage sensitivity is defined as deflection per unit volt. Voltage sensitivity for m₂ is given by.
(B) Voltage Sensitivity For M 2 Is Given As:
If the input resistance of the meter is 0.010 ohms, then 0.070 ohms is allowed for loop resistance of the wire, and connections between the current transformer and the meter. In a negative feedback amplifier, voltage sampling. The length and gauge of the wire must be considered in order to avoid exceeding the maximum burden.
Maximum Resistance = Voltage / Current = 04.00 Volts / 5 Amps =0.080 Ohms.
Hence, there is no increase in voltage sensitivity. Current sensitivity can be increased by increasing the number of turns of the coil. The voltage sensitivity of a galvanometer is given by _____ a) s v = e ⁄ Īø b) s v = Īø ⁄ e c) s v = 1 ⁄ e d) s v = 1 ⁄ Īø answer:
Therefore The Ratio Of Voltage Sensitivity And To The Current Sensitivity Of A Galvanometer Gives Conductance.
But increasing the number of turns correspondingly increases the resistance (g). In order that each division reads 1 volt, the resistance required to be connected in series with coil will be. So, we can say, voltage sensitivity = Īø/v = (nab/kr) where, Īø is the angular displacement, i.e.
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